CREATE TABLE Temp (
menu smallint ,
option_type char(1) ,
option_val char(1));
INSERT INTO Temp VALUES
(1, 'A', '1') , (1, 'A', '2'),
(2, 'A', '1') , (2, 'A', '2'), (2, 'B', '1'), (2, 'B', '2'),
(3, 'A', '1') , (3, 'A', '2') , (3, 'B', '1') , (3, 'B', '2') , (3, 'C', '1') , (3, 'C', '2');
;
WITH CTE AS
(
SELECT
menu ,
option_type ,
option_val ,
CAST(option_type + option_val AS varchar(8000)) AS Memo ,
CAST(1 as int) AS Stat
FROM Temp
UNION ALL
SELECT
T2.menu ,
T2.option_type ,
T2.option_val ,
T1.Memo + '_' + T2.option_type + T2.option_val ,
CAST(Stat + 1 as int) AS Stat
FROM Temp AS T2
JOIN CTE AS T1 ON T2.menu = T1.menu
AND T2.option_type > T1.option_type
)
SELECT
F1.*
FROM CTE AS F1
JOIN
(
SELECT
menu ,
COUNT(DISTINCT option_type) AS Stat
FROM Temp
GROUP BY menu
) AS F2 ON F1.menu = F2.menu
AND F1.stat = F2.stat
ORDER BY menu , memo
星期二, 1月 02, 2024
[SQL] 產品組合
在 論壇 上看見的問題,需求是要組合每個 menu 內產品,該 menu 內假如有三個產品的話,產品組合就只要三個產品的組合,兩個產品的組合就過濾掉不需要出現,資料來源和期待結果如下圖
透過 CTE 遞迴來處理產品組合
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